Calculate the power output of a ${}_{92}^{235}U$ reactor, if it takes $30 \, \text{days}$ to consume $2 \, \text{kg}$ of fuel, and if each fission releases $185 \, \text{MeV}$ of usable energy. (Given: Avogadro's number $= 6 \times 10^{23} \, \text{mol}^{-1}$) .......... $\text{MW}$ (in $.3$)

In nuclear fission,the fission reaction proceeds with a projectile. Which of the following suits the best?

If the energy released in the fission of one nucleus is $200 \, MeV$, then the number of nuclei required per second in a power plant of $16 \, kW$ will be:

Complete the reaction: $n + _{92}^{235}U \to _{56}^{144}Ba + .... + 3n$

$A$ nucleus with mass number $240$ breaks into two fragments each of mass number $120$. The binding energy per nucleon of the unfragmented nucleus is $7.6 \, MeV$,while that of the fragments is $8.5 \, MeV$. The total gain in the binding energy in the process is (in $MeV$):

Consider the fission of $_{92}^{238} U$ by fast neutrons. In one fission event,no neutrons are emitted and the final end products,after the beta decay of the primary fragments,are $_{58}^{140} Ce$ and $_{44}^{99} Ru$. Calculate the $Q$-value for this fission process. The relevant atomic and particle masses are:
$m(_{92}^{238} U) = 238.05079 \; u$
$m(_{58}^{140} Ce) = 139.90543 \; u$
$m(_{44}^{99} Ru) = 98.90594 \; u$
$m(_{0}^{1} n) = 1.008665 \; u$